Find string using pattern and return only the matched string

hi all

scratching head 1 , use help.

have file contains sddl dump.  trying find each sid in file , write value variable.  following regular expression seems provide pattern match.

"s-(.)*\)"

when run following commend returns whole file contents

select-string -path $file -pattern "s-(.)*\)"

want return strings matching pattern , not entire file contents.  understand output select-string matchinfo object, can't see properties or methods me extract string matching pattern.

thoughts?

tony

i've reached [regex]::matches when i've had this.  not easy 1 like...

get-content -path data.txt | %{ [regex]::matches($_, "s-[0-9\-]*") } | %{ $_.value }

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